Iceberg is a member of the rummy family, wherein points are earned for playing sets of the same rank or sequences of cards from the same suit. There are a couple of new twists in the scoring and play, however, that set Iceberg apart from all other members of the rummy family.
Any number from two up to about five or six can play. With 2 or 3, use a single deck; with 4 or more, shuffle two regular decks together. Each player is dealt seven cards initially. The remainder of the pack is placed face-down in the middle of the table.
Play rotates clockwise around the table, beginning with the player at dealer's right. Each player, at his turn, does the following:
Cards left in one's hand at the end of the game count -10 each. Any playable cards left in one's hand are an additional minus: however much they would have counted for you, had you been given another turn, they now count against you.
Aces do not take part in any of the above melds. They act as multipliers -- with no aces, you receive your score as earned above. Each player holding one ace earns double the above scores; two aces, triple; three aces, quadruple; and so on.
Recommended finishing score for a 2-person game is 5000. I haven't played the 3+ player versions enough to know what an appropriate finishing score for them is.
Player A is dealt 987, J3, QA and draws the 3. He plays his A and the 9-8-7, scoring 30. He discards the J.
Player B was dealt KJ3 Q J8 J and draws the 6. He plays the J and J, scoring 10, holding onto the J, which will be worth 50 if someone plays the ten. He discards the 8.
Player C was dealt: 6 10942 KQ. He draws the A from the stock and picks up the J discarded by player A. He plays the ace; his jack of hearts, which is worth 20 when added to B's pair; and the 6, worth 40 on A's run. He discards the 2.
Player A holds 3 Q 3, picks up the 8, and draws the Q. He plays his two pairs for 10 each and goes out by throwing the diamond away.
SCORE: Player A earned 30+10+10=50, which is doubled to 100 because he had one ace. Player B is stuck holding KJ3 Q 6. He earned 10, but loses 50 for holding 5 cards; 40 for the playable jack of spades; and 20 for the playable queen of hearts, for a total of -100. Player C is stuck holding 1094 KQ. The queen of clubs counts -20 (only two queens actually got played) and the 5 cards count -50. His net score is (20+40-20-50)x2=-20.
This game is simple, but there is scope for a lot of technical and psychological strategy. I can usually do fairly well at it, but I have not discovered the secret of winning consistently at it. Enjoy! Please feel free to tell me what you think of the game!Back to the Games page
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This page was last updated on 02.12.97.