
Yay! Classes are over! Soon I'm going to Paris for three weeks, to talk with PaulAndré Melliès about logic, games and category theory. But right now I'm in a vacation mood. So, I want to take a break from the Tale of Groupoidification, and mention some thoughts prompted by the work of Garrett Lisi:
1) Garrett Lisi, Deferential Geometry, http://deferentialgeometry.org.
Garrett is a cool dude who likes to ponder physics while living a lowbudget, highfun lifestyle: hanging out in Hawaii, surfing, and stuff like that. He recently won a Foundational Questions Institute award to think about ways to unify particle physics and gravity. That's an institute devoted precisely to risky endeavors like this.
Lately he's been visiting California. So, before giving a talk at Loops '07  a loop quantum gravity conference taking place in Mexico this week  he stopped by Riverside to explain what he's been up to.
Briefly, he's been trying to explain the 3 generations of elementary particles using some math called "triality", which is related to the octonions and the exceptional Lie groups. In fact, he's trying to use the exceptional Lie group E8 to describe all the particles in the Standard Model, together with gravity.
I'd like to know if these ideas hold water. So, I should try to explain them! But as usual, in this Week's Finds I'll wind up explaining not what Garrett actually did, but what it made me think about.
For a long time, people have been seeking connections between the messy pack of particles that populate the Standard Model and structures that seem beautiful and "inevitable".
A fascinating step in this direction was the SU(5) grand unified theory proposed in 1975 by Georgi and Glashow. So, I'll start by summarizing that... and then explain how exceptional Lie groups might get involved in this game.
What people usually call the gauge group of the Standard Model:
SU(3) × SU(2) × U(1)
actually has a bit of flab in it: there's a normal subgroup that acts trivially on all known particles. This subgroup is isomorphic to Z/6. If we mod out by this, we get the "true" gauge group of the Standard Model:
G = (SU(3) × SU(2) × U(1))/(Z/6)
And, this turns out to have a neat description. It's isomorphic to the subgroup of SU(5) consisting of matrices like this:
(g 0) (0 h)where g is a 3×3 block and h is a 2×2 block. For obvious reasons, I call this group
S(U(3) × U(2))
If you want some intuition for this, think of the 3×3 block as related to the strong force, and the 2×2 block as related to the electroweak force. A 3×3 matrix can mix up the 3 "colors" that quarks come in  red, green, and blue  and that's what the strong force is all about. Similarly, a 2×2 matrix can mix up the 2 "isospins" that quarks and leptons come in  up and down  and that's part of what the electroweak force is about.
If this isn't enough to make you happy, go back to "week119", where I reviewed the Standard Model and its relation to the SU(5) grand unified theory. If even that isn't enough to make you happy, try this:
2) John Baez, Elementary particles, http://math.ucr.edu/home/baez/qgspring2003/elementary/
Okay  I'll assume that one way or another, you're happy with the idea of S(U(3) × U(2)) as the true gauge group of the Standard Model! Maybe you understand it, maybe you're just willing to nod your head and accept it.
Now, the fermions of the Standard Model form a very nice representation of this group. SU(5) has an obvious representation on C^{5}, via matrix multiplication. So, it gets a representation on the exterior algebra Λ(C^{5}). If we restrict this from SU(5) to S(U(3) × U(2)), we get precisely the representation of the true gauge group of the Standard Model on one generation of fermions and their antiparticles!
This really seems like a miracle when you first see it. All sorts of weird numbers need to work out exactly right for this trick to succeed. For example, it's crucial that quarks have charges 2/3 and 1/3, while leptons have charges 0 and 1. One gets the feeling, pondering this stuff, that there really is some truth to the SU(5) grand unified theory.
To give you just a little taste of what's going on, let me show you how the exterior algebra Λ(C^{5}) corresponds to one generation of fermions and their antiparticles. For simplicity I'll use the first generation, since the other two work just the same:
Λ^{0}(C^{5}) ≅ <lefthanded antineutrino> Λ^{1}(C^{5}) ≅ <righthanded down quark> ⊕ <righthanded positron, righthanded antineutrino> Λ^{2}(C^{5}) ≅ <lefthanded up antiquark> ⊕ <lefthanded up quark, lefthanded down quark> ⊕ <lefthanded positron> Λ^{3}(C^{5}) ≅ <righthanded electron> ⊕ <righthanded up antiquark, righthanded down antiquark> ⊕ <righthanded up quark> Λ^{4}(C^{5}) ≅ <lefthanded up antiquark> ⊕ <lefthanded electron, lefthanded neutrino> Λ^{5}(C^{5}) ≅ <righthanded neutrino>All the quarks and antiquarks come in 3 colors, which I haven't bothered to list here. Each space Λ^{p}(C^{5}) is an irreducible representation of SU(5), but most of these break up into several different irreducible representations of S(U(3) × U(2)), which are listed as separate rows in the chart above.
If you're curious how this "breaking up" works, let me explain  it's sort of pretty. We just use the splitting
C^{5} ≅ C^{3} ⊕ C^{2}
to chop the spaces Λ^{p}(C^{5}) into pieces.
To see how this works, remember that Λ^{p}(C^{5}) is just the vector space analogue of the binomial coefficient "5 choose p". A basis of C^{5} consists of 5 things, and the pelement subsets give a basis for Λ^{p}(C^{5}).
In our application to physics, these 5 things consist of 3 "colors"  red, green and blue  and 2 "isospins"  up and down. This gives various possible options.
For example, suppose we want a basis of Λ^{3}(C^{5}). Then we need to pick 3 things out of 5. We can do this in various ways:
So, in terms of binomial coefficients, we have
(5 choose 3) = (3 choose 3)(2 choose 0) + (3 choose 2)(2 choose 1) + (3 choose 1)(2 choose 2) = 1 + 6 + 3 = 10
In terms of vector spaces we have:
Λ^{3}(C^{5}) ≅ Λ^{3}(C^{3}) ⊗ Λ^{0}(C^{2}) ⊕ Λ^{2}(C^{3}) ⊗ Λ^{1}(C^{2}) ⊕ Λ^{1}(C^{3}) ⊗ Λ^{2}(C^{2})
Taking dimensions of these vector spaces, we get 10 = 1 + 6 + 3. Finally, in terms of the SU(5) grand unified theory, we get this:
Λ^{3}(C^{5}) = <righthanded electron> ⊕ <righthanded up antiquark, righthanded down antiquark> ⊕ <righthanded up quark>If we play this game for all the spaces Λ^{p}(C^{5}), here's what we get:
Λ^{0}(C^{5}) ≅ Λ^{0}(C^{3}) ⊗ Λ^{0}(C^{2}) Λ^{1}(C^{5}) ≅ Λ^{1}(C^{3}) ⊗ Λ^{0}(C^{2}) ⊕ Λ^{0}(C^{3}) ⊗ Λ^{1}(C^{2}) Λ^{2}(C^{5}) ≅ Λ^{2}(C^{3}) ⊗ Λ^{0}(C^{2}) ⊕ Λ^{1}(C^{3}) ⊗ Λ^{1}(C^{2}) ⊕ Λ^{0}(C^{3}) ⊗ Λ^{2}(C^{2}) Λ^{3}(C^{5}) ≅ Λ^{3}(C^{3}) ⊗ Λ^{0}(C^{2}) ⊕ Λ^{2}(C^{3}) ⊗ Λ^{1}(C^{2}) ⊕ Λ^{1}(C^{3}) ⊗ Λ^{2}(C^{2}) Λ^{4}(C^{5}) ≅ Λ^{3}(C^{3}) ⊗ Λ^{1}(C^{2}) ⊕ Λ^{2}(C^{2}) ⊗ Λ^{2}(C^{2}) Λ^{5}(C^{5}) ≅ Λ^{3}(C^{3}) ⊗ Λ^{2}(C^{2})If we interpret this in terms of physics, we get back our previous chart:
Λ^{0}(C^{5}) ≅ <lefthanded antineutrino> Λ^{1}(C^{5}) ≅ <righthanded down quark> ⊕ <righthanded positron, righthanded antineutrino> Λ^{2}(C^{5}) ≅ <lefthanded up antiquark> ⊕ <lefthanded up quark, lefthanded down quark> ⊕ <lefthanded positron> Λ^{3}(C^{5}) ≅ <righthanded electron> ⊕ <righthanded up antiquark, righthanded down antiquark> ⊕ <righthanded up quark> Λ^{4}(C^{5}) ≅ <lefthanded up antiquark> ⊕ <lefthanded electron, lefthanded neutrino> Λ^{5}(C^{5}) ≅ <righthanded neutrino>
Now, all this is really cool  but in fact, even before inventing the SU(5) theory, Georgi went a bit further, and unified all the lefthanded fermions above into one irreducible representation of a somewhat bigger group: Spin(10). This is the double cover of the group SO(10), which describes rotations in 10 dimensions.
If you look at the chart above, you'll see the lefthanded fermions live in the even grades of the exterior algebra of C^{5}:
Λ^{even}(C^{5}) = Λ^{0}(C^{5}) ⊕ Λ^{2}(C^{5}) ⊕ Λ^{4}(C^{5})
This big space forms something called the lefthanded Weyl spinor representation of Spin(10). It's an irreducible representation.
Similarly, the righthanded fermions live in the odd grades:
Λ^{odd}(C^{5}) = Λ^{1}(C^{5}) ⊕ Λ^{3}(C^{5}) ⊕ Λ^{5}(C^{5})
and this big space forms the righthanded Weyl spinor representation of Spin(10). It's also irreducible.
I can't resist mentioning that there's also a gadget called the Hodge star operator that maps Λ^{even}(C^{5}) to Λ^{odd}(C^{5}), and vice versa. In terms of physics, this sends lefthanded particles into their righthanded antiparticles, and vice versa!
But if I get into digressions like these, it'll take forever to tackle the main question: how does this "Weyl spinor" stuff work?
It takes advantage of some very nice general facts. First, C^{n} is just another name for R^{2n} equipped with the structure of a complex vector space. This makes SU(n) into a subgroup of SO(2n). So, it makes the Lie algebra su(n) into a Lie subalgebra of so(2n).
The group SU(n) acts on the exterior algebra Λ(C^{n}). So, its Lie algebra su(n) also acts on this space. The really cool part is that this action extends to all of so(2n). This is something you learn about when you study Clifford algebras, spinors and the like. I don't know how to explain it without writing down some formulas. So, for now, please take my word for it!
This business doesn't give a representation of SO(2n) on Λ(C^{n}), but it gives a representation of the double cover, Spin(2n). This is called the "Dirac spinor" representation. It breaks up into two irreducible parts:
Λ(C^{n}) = Λ^{even}(C^{n}) ⊕ Λ^{odd}(C^{n})
and these are called the left and righthanded "Weyl spinor" representations.
Perhaps it's time for an executive summary of what I've said so far:
The Dirac spinor representation of Spin(10) neatly encodes everything about how one generation of fermions interacts with the gauge bosons in the Standard Model, as long as we remember how S(U(2) × U(3)) sits inside SO(10), which is double covered by Spin(10).Of course, there's more to the Standard Model than this. There's also the Higgs boson, which spontaneously breaks electroweak symmetry and gives the fermions their masses. And, if we want to use this same trick to break the symmetry from Spin(10) down to S(U(3) × U(2)), we need to introduce more Higgs bosons. This is the ugly part of the story, it seems. Since I'm on vacation, I'll avoid it for now.
Next: how might exceptional Lie groups get involved in this game?
When Cartan classified compact simple Lie groups, he found 3 infinite families related to rotations in real, complex and quaternionic vector spaces: the SO(n)'s, SU(n)'s and Sp(n)'s. He also found 5 exceptions, which have the charming names G_{2}, F_{4}, E_{6}, E_{7}, and E_{8}. These are all related to the octonions. G_{2} is just the automorphism group of the octonions. The other 4 are closely related to each other  thanks to the "magic square" of Rosenfeld, Freudenthal and Tits.
I talked about the magic square a bit in "week106" and "week145", and much more here:
3) John Baez, The magic square, http://math.ucr.edu/home/baez/octonions/node16.html
Instead of repeating all that, let me just summarize. The magic square gives vector space isomorphisms as follows:
f_{4} ≅ so(R ⊕ O) ⊕ (R ⊗ O)^{2}
e_{6} ≅ so(C ⊕ O) ⊕ (C ⊗ O)^{2} ⊕ Im(C)
e_{7} ≅ so(H ⊕ O) ⊕ (H ⊗ O)^{2} ⊕ Im(H)
e_{8} ≅ so(O ⊕ O) ⊕ (O ⊗ O)^{2}
Here f_{4}, e_{6}, e_{7} and e_{8} stand for the Lie algebras of the compact real forms of these exceptional Lie groups. R, C, H, and O are the usual suspects  the real numbers, complex numbers, quaternions and octonions. For any real inner product space V, so(V) stands for the Lie algebra of the rotation group of V. And, for each of the isomorphisms above, we must equip the vector space on the right side with a cleverly (but not perversely!) defined Lie bracket to get the Lie algebra on the left side.
Here's another way to say the same thing, which may ring more bells:
f_{4} ≅ so(9) ⊕ S_{9}
e_{6} ≅ so(10) ⊕ S_{10} ⊕ u(1)
e_{7} ≅ so(12) ⊕ S_{12}^{+} ⊕ su(2)
e_{8} ≅ so(16) ⊕ S_{16}^{+}
Here S_{9} and S_{10} are the unique irreducible real spinor representations of so(9) and so(10), respectively. In the other two cases, the little plus signs mean that there are two choices of irreducible real spinor representation, and we're taking the lefthanded choice.
All this must seem like black magic of the foulest sort if you haven't wasted months thinking about the octonions and exceptional groups! Be grateful: I did it so you wouldn't have to.
Anyway: the case of E_{6} should remind you of something! After all, we've just been talking about so(10) and its lefthanded spinor representation. These describe the gauge bosons and one generation of lefthanded fermions in the Spin(10) grand unified theory. But now we're seeing this stuff neatly packed into the Lie algebra of E_{6}!
More precisely, the Lie algebra of E_{6} can be chopped into 3 pieces in a noncanonical way:
S_{10} ≅ Λ^{even}(C^{5}) ≅ (C ⊗ O)^{2}
The first part contains all the gauge bosons in the SO(10) grand unified theory. The second contains one generation of lefthanded fermions. But what about the third?
Well, S_{10} is defined to be a real representation of so(10). But, it just so happens that the action of so(10) preserves a complex structure on this space. This is just the obvious complex structure on (C ⊗ O)^{2}, or if you prefer, Λ^{even}(C^{5}). So, there's an action of the unit complex numbers, U(1), on S_{10} which commutes with the action of so(10). Differentiating this, we get an action of the Lie algebra u(1):
u(1) ⊗ S_{10} → S_{10}
And this map gives part of the cleverly defined Lie bracket operation in
e_{6} ≅ so(10) ⊕ S_{10} ⊕ u(1)
All this stuff is mysterious, but suggestive. It could be mere coincidence, or it could be the tip of an iceberg. It's more fun to assume the latter. So, let me say some more about it....
The copy of u(1) in here:
E_{6} ≅ so(10) ⊕ S_{10} ⊕ u(1)
is pretty amusing from a physics viewpoint. It's if besides the gauge bosons in so(10), there were one extra gauge boson whose sole role is to describe the fact that the fermions form a complex representation of so(10). This is funny, since one of the naive ideas you sometimes hear is that you can take the obvious U(1) symmetry every complex Hilbert space has and "gauge" it to get electromagnetism.
That's not really the right way to understand electromagnetism! There are lots of different irreducible representations of U(1), corresponding to different charges, and in physics we should think about all of these, not just the obvious one that we automatically get from any complex Hilbert space. If we only used the obvious one, all particles would have charge 1.
But in the Spin(10) grand unified theory, the electromagnetic u(1) Lie algebra is sitting inside so(10); it's not the u(1) you see above. The u(1) you see above is the "obvious" one that the spinor representation S_{10} gets merely from being a complex Hilbert space.
The splitting
e_{6} = so(10) ⊕ S_{10} ⊕ u(1)
also hints at a weird unification of bosons and fermions, something different from supersymmetry. We're seeing e_{6} as a Z/2graded Lie algebra with so(10) ⊕ u(1) as its "bosonic" part and S_{10} as its "fermionic" part. But, this is not a Lie superalgebra, just an ordinary Lie algebra with a Z/2 grading!
Furthermore, an ordinary Lie algebra with a Z/2 grading is precisely what we need to build a "symmetric space". This is really cool, since it explains what I meant by saying that the split of e_{6} into bosonic and fermionic parts is "noncanonical". We'll get a space, and each point in this space will give a different way of splitting e_{6} as
e_{6} = so(10) ⊕ S_{10} ⊕ u(1)
It's also cool because it gives me an excuse to talk about symmetric spaces... a topic that deserves a whole week of its own!
Symmetric spaces are the epitome of symmetry. A "homogeneous space" is a manifold with enough symmetry that any point looks like any other. A symmetric space is a homogeneous space with an extra property: the view from any point in any direction is the same as the view in the opposite direction!
Euclidean spaces and spheres are the most famous examples of symmetric spaces. If an ant decides to set up residence on a sphere, any point is just as good any other. And, if sits anywhere and looks in any direction, the view is the same as the view in the opposite direction.
The symmetric space we get from the above Z/2graded Lie algebra is similar, but more exotic: it's the complexified version of the octonionic projective plane!
But let's start with the basics:
Suppose someone hands you a Lie algebra g with a Lie subalgebra h. Then you can form the simplyconnected Lie group G whose Lie algebra is g. Sitting inside G, there's a connected Lie group H whose Lie algebra is h. The space
G/H
is called a "homogeneous space". Such things are studied in Klein geometry, and I've been talking about them a lot lately.
But now, suppose g is a Z/2graded Lie algebra. Its even part will be a Lie subalgebra; call this h. This gives a specially nice sort of homogeneous space G/H, called a "symmetric space". This is better than your average homogeneous space.
Why? Well, first of all, for each point p in G/H there's a map from G/H to itself called "reflection through p", which fixes the point p and acts as 1 on the tangent space of p. When our point p comes from the identity element of G, this reflection map corresponds to the Z/2 grading of the Lie algebra, which fixes the even part and acts as 1 on the odd part.
This is what I meant by saying that in a symmetric space, "the view in any direction is the same as the view in the opposite direction".
Second, these reflection maps satisfy some nice equations. Write p>q for the the result of reflecting q through p. Then we have:
p>(p>q) = q
p>p = p
and
p>(q>r) = (p>q) > (p>r)
A set with an operation satisfying these equations is called an "involutory quandle". Quandles are famous in knot theory. Now we're seeing them in another role.
Let me summarize with a few theorems  I hope they're all true, because I don't know a book containing all this stuff. We can define a "symmetric space" to be an involutory quandle that's a manifold, where the operation > is smooth and the reflection map
x → p>x
has derivative 1 at p. Any Z/2graded Lie algebra gives a symmetric space. Conversely, any symmetric space has a universal cover that's a symmetric space coming from a Z/2graded Lie algebra!
Using this correspondence, the Lie algebra e_{6} with the Z/2grading I described gives a symmetric space, roughly:
E_{6}/(Spin(10) × U(1))
But, this guy is a lot better than your average symmetric space!
For starters, it's a "Riemannian symmetric space". This is a symmetric space with a Riemannian metric that's preserved by all the operations of reflection through points.
Compact Riemannian symmetric spaces were classified by Cartan, and you can see the classification here, in a big chart:
4) Riemannian symmetric spaces, Wikipedia, http://en.wikipedia.org/wiki/Riemannian_symmetric_space
As you'll see, there are 7 infinite families and 12 exceptional cases. The symmetric space I'm talking about now, namely E_{6}/(Spin(10) × U(1)), is called EIII  it's the third exceptional case. And, as you can see from the chart in this article, it's the complexified version of the octonionic projective plane! For this reason, I sometimes call it
(C ⊗ O)P^{2}
In fact, this space is better than your average Riemannian symmetric space. It's a Kähler manifold, thanks to that copy of U(1), which makes each tangent space complex. Moreover, the Kähler structure is preserved by all the operations of reflection through points. So, it's a "hermitian symmetric space".
You're probably drowning under all this terminology unless you already know this stuff. I guess it's time for another executive summary:
Each point in the complexified octonionic projective plane gives a different way of splitting the Lie algebra of E_{6} into a bosonic part and a fermionic part. The fermionic part is just what we need to describe one generation of lefthanded Standard Model fermions. The bosonic part is just what we need for the gauge bosons of the Spin(10) grand unified theory, together with a copy of u(1), which describes the complex structure of the lefthanded Standard Model fermions.
Another nice fact is that (C ⊗ O)P^{2} is one of the Grassmannians for E_{6}. I explained this general notion of "Grassmannian" back in "week181", and you can see this 16dimensional one in the list near the end of that Week.
Even better, if you geometrically quantize this Grassmannian using the smallest possible symplectic structure, you get the 27dimensional representation of E_{6} on the exceptional Jordan algebra!
So, there's a lot of seriously cool math going on here... but since the basic idea of relating the Standard model to E_{6} is only halfbaked, all the ideas I'm mentioning now are at best quarterbaked. They're mathematically correct, but I can't tell if they're leading somewhere interesting.
In fact, I would have kept them in the oven longer had not Garrett Lisi brought E_{6}'s big brother E_{8} into the game in a tantalizing way. I'll conclude by summarizing this... and you can look at his website for more details. But first, let me emphasize that this E_{8} business is the most recent and most speculative thing Garrett has done. So, if you think the following idea is nuts, please don't jump to conclusions and decide everything he's doing is nuts!
Briefly, his idea involves taking the description of e_{8} I already mentioned:
e_{8} = so(O ⊕ O) ⊕ (O ⊗ O)^{2}
and writing the linear transformations in so(O ⊕ O) as two 8×8 blocks living in so(O), together with an offdiagonal block living in O ⊗ O. This gives
e_{8} = so(O) ⊕ so(O) ⊕ (O ⊗ O)^{3}
Then, he wants to use each of the three copies of O ⊗ O to describe one of the three generations of fermions, while using the so(O) ⊕ so(O) stuff to describe bosons (including gravity).
For this, he builds on some earlier work where he sought to combine gravity, the Standard Model gauge bosons, the Higgs and one generation of Standard Model fermions in an so(7,1) version of MacDowellMansouri gravity.
If I were really being responsible, I would describe and assess this earlier work. But, it's summer and I just want to have fun....
In fact, the above alternate description of E_{8} is the one Bertram Kostant told me about back in 1996. He said it a different way, which is equivalent:
E_{8} = so(8) ⊕ so(8) ⊕ End(V_{8}) ⊕ End(S_{8}^{+}) ⊕ End(S_{8}^{})
Here V_{8}, S_{8}^{+} and S_{8}^{} are the vector, lefthanded spinor, and righthanded spinor representations of Spin(8). All three are 8dimensional, and all are related by outer automorphisms of Spin(8). That's what "triality" is all about. You can see more details in "week90".
The idea of relating the three generations to triality is cute. Of course, even if it worked, you'd need something to give the fermions in different generations different masses  which is what happens already in the Standard Model, thanks to the Higgs boson. It's the bane of all postStandard Model physics: symmetry looks nice, but the more symmetry your model has, the more symmetries you need to explain away! As the White Knight said to Alice:
But I was thinking of a plan
To dye one's whiskers green,
And always use so large a fan
That they could not be seen.
Someday we may think of a way around this problem. But for now, I've got a more pressing worry. This splitting of E_{6}:
E_{6} = so(10) ⊕ S_{10}^{+} ⊕ u(1)
corresponds to a Z/2grading where so(10) ⊕ u(1) is the "bosonic" or "even" part and S_{10}^{+} is the "fermionic" or "odd" part. This nicely matches the way so(10) describes gauge bosons and S_{10}^{+} describes fermions in Georgi's grand unified theory. But, this splitting of E_{8}:
E_{8} = so(8) ⊕ so(8) ⊕ End(V_{8}) ⊕ End(S_{8}^{+}) ⊕ End(S_{8}^{})
does not correspond to any Z/2grading where so(8) ⊕ so(8) is the bosonic part and End(V) ⊕ End(S^{+}) ⊕ End(S^{}) is the fermionic part. There is a closely related Z/2grading of E_{8}, but it's this:
E_{8} = so(16) ⊕ S_{16}^{+}
So, right now I don't feel it's mathematically natural to use this method to combine bosons and fermions.
But, only time will tell.
Here are some more references. The SU(5) grand unified theory was published here:
5) Howard Georgi and Sheldon Glashow, Unity of all elementaryparticle forces, Phys. Rev. Lett. 32 (1974), 438.
For a great introduction to the Spin(10) grand unified theory  which is usually called the SO(10) GUT  try this:
6) Anthony Zee, Quantum Field Theory in a Nutshell, Chapter VII: SO(10) unification, Princeton U. Press, Princeton, 2003.
Then, try these more advanced review articles:
7) Jogesh C. Pati, Proton decay: a must for theory, a challenge for experiment, available as hepph/0005095.
8) Jogesh C. Pati, Probing grand unification through neutrino oscillations, leptogenesis, and proton decay, available as hepph/0305221.
The last two also consider the gauge group "G(224)", meaning SU(2) × SU(2) × SU(4).
By the way, there's also a cute relation between the SO(10) grand unified theory and 10dimensional CalabiYau manifolds, discussed here:
9) John Baez, CalabiYau manifolds and the Standard Model, available as hepth/0511086
This is an easy consequence of the stuff I've explained this week.
To see what string theorists are doing to understand the Standard Model these days, see the following papers. Amusingly, they also use E_{8}  but in a quite different way:
10) Volker Braun, YangHui He, Burt A. Ovrut and Tony Pantev, A heterotic Standard Model, available as hepth/0501070.
A Standard Model from the E_{8} × E_{8} heterotic superstring, hepth/0502155.
Vector bundle extensions, sheaf cohomology, and the heterotic Standard Model, available as hepth/0505041.
Heterotic Standard Model moduli, available as hepth/0509051.
The exact MSSM spectrum from string theory, available as hepth/0512177.
All this stuff is really cool  but alas, they get the "minimal supersymmetric Standard Model", or MSSM, which has a lot more particles than the Standard Model, and a lot more undetermined parameters. Of course, these flaws could become advantages if the next big particle accelerator, the Large Hadron Collider, sees signs of supersymmetry.
For more on symmetric spaces, try these:
11) Sigurdur Helgason, Differential Geometry, Lie Groups, and Symmetric Spaces, AMS, Providence, Rhode Island, 2001.
12) Audrey Terras, Harmonic Analysis on Symmetric Spaces and Applications I, Springer, Berlin, 1985. Harmonic Analysis on Symmetric Spaces and Applications II, Springer, Berlin, 1988.
13) Arthur Besse, Einstein Manifolds, Springer, Berlin, 1986.
They're all classics. Helgason's book will teach you differential geometry and Lie groups before doing Cartan's classification of symmetric spaces. Terras' books are full of fun connections to other branches of math. Besse's book has lots of nice charts, and goes much deeper into the Riemannian geometry of symmetric spaces.
These dig deeper into the algebraic aspects of symmetric spaces:
14) W. Bertram, The Geometry of Jordan and Lie structures, Lecture Notes in Mathematics 1754, Springer, Berlin, 2001.
15) Ottmar Loos, Jordan triple systems, Rspaces and bounded symmetric domains, Bull. AMS 77 (1971), 558561.
16) Ottmar Loos, Symmetric Spaces I: General Theory, W. A. Benjamin, New York, 1969. Symmetric Spaces II: Compact Spaces and Classification, W. A. Benjamin, New York, 1969.
Finally, an obnoxious little technical note. The complexification of the octonionic projective plane is not really E_{6}/(Spin(10) × U(1)); it's
E_{6}/((Spin(10) × U(1))/(Z/4))
This is worked out here:
17) John Frank Adams, Lectures on Exceptional Lie Groups, eds. Zafer Mahmud and Mamoru Mimura, University of Chicago Press, Chicago, 1996.
Addendum: Joseph Hucks points out his paper describing the 13 different groups with Lie algebra su(3) ⊕ su(2) ⊕ u(1), and their implications for physics:
18) Joseph Hucks, Global structure of the standard model, anomalies, and charge quantization, Phys. Rev. D 43 (1991), 27092717.
Using S(U(3) × U(2)) and demanding anomaly cancellation, we automatically get a lot of the features of the Standard Model fermions.
Toby Bartels wisely points out that my basic examples of symmetric spaces  Euclidean spaces and sphere  are actually a bit misleading. I'd written:
Euclidean spaces and spheres are the most famous examples of symmetric spaces. If an ant decides to set up residence on a sphere, any point is just as good any other. And, if sits anywhere and looks in any direction, the view is the same as the view in the opposite direction.But in these particular examples, the view in any direction is the same as the view in any other direction! These spaces are more symmetrical than your average symmetric space: they're isotropic.
So, it's good to see some other examples, like a torus formed as the product of two circles of different radii. Any product of symmetric spaces is a symmetric space, so this is definitely a symmetric space. And, if you think about it, the ant'seye view in any direction is just the same as the view in the opposite direction. But, this space is not isotropic: there are special directions, corresponding to "the short way around the torus" and "the long way around the torus".
The octonionic projective plane OP^{2} is not only a symmetric space: it's isotropic! But according to Tony Smith, the complexified version (C ⊗ O)P^{2} is not isotropic:
In Spaces of Constant Curvature, Fifth Edition (Publish or Perish 1984), Joseph A. Wolf says (pages 293294):Since (C ⊗ O)P^{2} = E_{6}/(SO(10) × SO(2)) is rank 2, it is NOT isotropic.... M is called isotropic at x if I(M)_{x} is transitive on the unit sphere in M_{x}; it is isotropic if it is isotropic at every point. ... M is isotropic if and only if it is two point homogeneous. ... Let M be a riemannian symmetric space. Then the following conditions are equivalent. (i) M is two point homogeneous. (ii) Either M is a euclidean space or M is irreducible and of rank 1.
In the quote by Wolf, I can only guess that I(M)_{x} is the group of isometries of M that fix the point x, while M_{x} is the tangent space of M at x. Similarly, I guess that "two point homogeneous" means that for any D ≥ 0, the isometry group of M acts transitively on the set of pairs of points in M whose distance from each other is D.
I also thank Tony for correcting some errors involving spinors. There's some quite subtle stuff going on here. For example, above it says that:
Well, S_{10} is defined to be a real representation of so(10). But, it just so happens that the action of so(10) preserves a complex structure on this space. This is just the obvious complex structure on (C ⊗ O)^{2}, or if you prefer, Λ^{even}(C^{5}). So, there's an action of the unit complex numbers, U(1), on S_{10}^{+} which commutes with the action of so(10).But in fact, so(10) preserves two complex structures on S_{10}. This is how it always works: if some complex structure J is preserved by some group or Lie algebra action, so is J. In the case at hand, one of these makes the representation of so(10) into a complex representation isomorphic to its lefthanded Weyl spinor representation on Λ^{even} (C^{5}). The other gives the righthanded Weyl spinor representation on Λ^{odd}(C^{5}). Neither one of these is "more correct" than the other. So, whenever I talk about e_{6} as being related to one generation of lefthanded Standard Model fermions, I could equally well say "righthanded Standard Model fermions". It just depends on which complex structure we choose!
Furthermore, when we complexify the real Lie algebra e_{6}, we get
C ⊗ e_{6} ≅ so(10,C) ⊕ Λ(C^{5}) ⊕ C
where Λ(C^{5}) is the Dirac spinor representation of so(10,C), describing both left and righthanded fermions.
For more discussion, go to the nCategory CafĂ©.
© 2007 John Baez
baez@math.removethis.ucr.andthis.edu
