**karatsuba multiplication in sbcl**

Possible alternative title: I’m on a train!

In particular, I’m on the train heading to the European Lisp Symposium, and for the first time since December I don’t have a criticially urgent piece of teaching to construct. (For the last term, I’ve been under the cosh of attempting to teach Algorithms & Data Structures to a class, having never learnt Algorithms & Data Structures formally, let along properly, myself).

I have been giving the students some structure to help them in their
learning by constructing multiple-choice quizzes. “But
multiple-choice quizzes are easy!”, I hear you cry! Well, they might
be in general, but these quizzes were designed to probe some
understanding, and to help students recognize what they did not know;
of the ten quizzes I ran this term, several had a period where the
modal mark in the quiz was zero. (The students were allowed take the
quizzes more than once; the idea behind that being that they can learn
from their mistakes and improve their score; the score is correlated
to a mark in some minor way to act as a tiny carrot-bite of
motivation; this means I have to write *lots* of questions so that
multiple attempts aren’t merely an exercise in memory or screenshot
navigation).

The last time I was on a train, a few weeks ago, I was travelling to and from Warwick to sing Haydn’s Nelson Mass (“Missa in angustiis”; troubled times, indeed), and had to write a quiz on numbers. I’d already decided that I would show the students the clever Karatsuba trick for big integer multiplication, and I wanted to write some questions to see if they’d understood it, or at least could apply some of the results of it.

Standard multiplication as learnt in school is, fairly clearly, an
Ω(d^{2}) algorithm. My children learn to multiply using the
“grid method”, where: each digit value of the number is written out
along the edges of a table; the cells of the table are the products of
the digit values; and the result is found by adding the cells
together. Something like:

` ````
400 20 7
300 120000 6000 2100
90 36000 1800 630
3 1200 60 21
```

for 427×393 = 167811. Similar diagrammatic ways of multiplying (like [link]) duplicate this table structure, and traditional long multiplication or even the online multiplication trick where you can basically do everything in your head all multiply each digit of one of the multiplicands with each digit of the other.

But wait! This is an Algorithms & Data Structures class, so there
must be some recursive way of decomposing the problem into smaller
problems; divide-and-conquer is classic fodder for Computer
Scientists. So, write a×b as
(a_{hi}×2^{k}+a_{lo})×(b_{hi}×2^{k}+b_{lo}),
multiply out the brackets, and hi and lo and behold we have
a_{hi}×b_{hi}×2^{2k}+(a_{hi}×b_{lo}+a_{lo}×b_{hi})×2^{k}+a_{lo}×b_{lo},
and we’ve turned our big multiplication into four multiplications of
half the size, with some additional simpler work to combine the
results, and big-O dear! that’s still quadratic in the number of
digits to multiply. Surely there is a better way?

Yes there is.
Karatsuba multiplication
is a better (asymptotically at least) divide-and-conquer algorithm.
It gets its efficiency from a clever
observation[1]: that middle term in
the expansion is expensive, and in fact we can compute it more
cheaply. We have to calculate
c_{hi}=a_{hi}×b_{hi} and
c_{lo}=a_{lo}×b_{lo}, there’s no getting
around that, but to get the cross term we can compute
(a_{hi}+a_{lo})×(b_{hi}+b_{lo}) and
subtract off c_{hi} and c_{lo}: and that’s then one
multiply for the result of two. With that trick, Karatsuba
multiplication lets us turn our big multiplication into three
multiplications of half the size, and that eventaully
boils down to an
algorithm with complexity Θ(d^{1.58}) or thereabouts. Hooray!

Some of the questions I was writing for the quiz were for the students
to compute the complexity of variants of Karatsuba’s trick: generalize
the trick to cross-terms when the numbers are divided into thirds
rather than halves, or quarters, and so on. You can multiply numbers
by doing six multiplies of one-third the size, or ten multiplies of
one-quarter the size, or... wait a minute! Those generalizations of
Karatsuba’s trick are *worse*, not better! That was completely
counter to my intuition that a generalization of Karatsuba’s trick
should be asymptotically better, and that there was probably some
sense in which the limit of doing divide-bigly-and-conquer-muchly
would turn into an equivalent of FFT-based multiplication with
Θ(d×log(d)) complexity. But this generalization was pulling me back
towards Θ(d^{2})! What was I doing wrong?

Well what I was doing wrong was applying the wrong generalization. I
don’t feel too much shame; it appears that Karatsuba did the same. If
you’re
Toom or Cook,
you probably see straight away that the right generalization is not to
be clever about how to calculate cross terms, but to be clever about
how to multiply polynomials: treat the divided numbers as polynomials
in 2^{k}, and use the fact that you need one more value than
the polynomial’s degree to determine all its coefficients. This gets
you a product in five multiplications of one-third the size, or seven
multiplications of one-quarter, and this is much better and fit with
my intuition as to what the result should be. (I decided that the
students could do without being explicitly taught about all this).

Meanwhile, here I am on my train journey of relative freedom, and I thought it might be interesting to see whether and where there was any benefit to implement Karatsuba multiplication in SBCL. (This isn’t a pedagogy blog post, or an Algorithms & Data Structures blog post, after all; I’m on my way to a Lisp conference!). I had a go, and have a half-baked implementation: enough to give an idea. It only works on positive bignums, and bails if the numbers aren’t of similar enough sizes; on the other hand, it is substantially consier than it needs to be, and there’s probably still some room for micro-optimization. The results?

The slopes on the built-in and Karatsuba mulitply (according to the
linear model fit) are 1.85±0.04 and 1.52±0.1 respectively, so even
million-(binary)-digit bignums aren’t clearly in the asymptotic
régimes for the two multiplication methods: but at that size (and even
at substantially smaller sizes, though not quite yet at Juho’s
1000 bits) my
simple Karatsuba implementation is clearly faster than the built-in
multiply. I should mention that at least part of the reason that I
have even *heard* of Karatsuba multiplication is Raymond Toy’s
implementation of it in
CMUCL.

Does anyone out there use SBCL for million-digit multiplications?

Syndicated 2017-04-02 20:45:22 (Updated 2017-04-02 20:48:17) from notes